Y=3x^2+x+5

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Solution for Y=3x^2+x+5 equation: 



=3Y^2+Y+5

We move all terms to the left:

-(3Y^2+Y+5)=0

We get rid of parentheses

-3Y^2-Y-5=0

We add all the numbers together, and all the variables

-3Y^2-1Y-5=0

a = -3; b = -1; c = -5;
Δ = b2-4ac
Δ = -12-4·(-3)·(-5)
Δ = -59
Delta is less than zero, so there is no solution for the equation

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